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	<title>BORZUYA UNIVERSITY &#187; Physics</title>
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		<title>Chapter 3a: the motion- the position</title>
		<link>http://brussels-scientific.com/?p=8644</link>
		<comments>http://brussels-scientific.com/?p=8644#comments</comments>
		<pubDate>Thu, 01 Feb 2018 10:48:18 +0000</pubDate>
		<dc:creator><![CDATA[Dr GERARD Thomas]]></dc:creator>
				<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[Physics]]></category>
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		<description><![CDATA[<p>The first formalism that has to be known in physics is the formalism of the motion. A formalism is associated with a certain rigorous mathematical method, defining symbols and rules that are commonly accepted, in the goal that everybody understands immediately the discussed matter. We will not be interested in the prediction of the motion nor [&#8230;]</p>
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=8644">Chapter 3a: the motion- the position</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
]]></description>
				<content:encoded><![CDATA[<p style="text-align: justify">The first formalism that has to be known in physics is the formalism of the motion. A formalism is associated with a certain rigorous mathematical method, defining symbols and rules that are commonly accepted, in the goal that everybody understands immediately the discussed matter. We will not be interested in the prediction of the motion nor its cause, but in its description alone.</p>
<p style="text-align: justify">In this section, we consider that every object can be considered as a dot without volume.</p>
<p style="text-align: justify"><span style="color: #0000ff"><strong>The position</strong></span></p>
<p style="text-align: justify">The motionis the history of the position of an object, the succession of the positions of this object over the time. To define the position of the object, we need a reference system in which we can give the position: coordinates. Several systems of reference exist and there are several ways to calculate the coordinates of objects. All of them are corrects but some are more convenient than the others. During a trip, you won’t give your position with regard to the sun, the same is true in physics.</p>
<p style="text-align: justify">Several coordinates are generally necessary to determine the exact position of one object. If you say that you are 10km from Paris, you give an information on your position but we are lacking at least one coordinate to determine your position. Usually you need one coordinate by dimension of the system.</p>
<p style="text-align: justify"><em><span style="text-decoration: underline"><span style="color: #0000ff;text-decoration: underline">One dimension</span></span></em></p>
<p style="text-align: justify">We choose one origin to the coordinate system, the zero point. It is convenient to choose the initial position of the object A as the origin but it is not mandatory. Next we choose a direction that will be the positive positions. In the opposite direction we have the negative positions. Still for convenience, the positive positions are placed in the direction we guess the object will move towards. Imagine that the object moves towards another object B placed at a distance d. The position vector indicates the distance between an object and the origin, and points towards the object with an arrow. The symbol for vectors is topped by an arrow pointing to the right. The position vector for B is</p>
<p><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim13.png" rel="lightbox-0"><img class="alignnone size-full wp-image-8645 aligncenter" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim13.png" alt="dim13" width="123" height="30" /></a></p>
<p style="text-align: justify">Where <a href="http://brussels-scientific.com/wp-content/uploads/2018/02/mov2.png" rel="lightbox-1"><img class="alignnone size-full wp-image-8674" src="http://brussels-scientific.com/wp-content/uploads/2018/02/mov2.png" alt="mov2" width="22" height="28" /></a> is the unit vector in the direction x (the single direction in this problem).</p>
<p><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/physics.png" rel="lightbox-2"><img class="alignnone size-full wp-image-8646 aligncenter" src="http://brussels-scientific.com/wp-content/uploads/2018/02/physics.png" alt="physics" width="567" height="265" /></a></p>
<p style="text-align: justify"><em><span style="text-decoration: underline"><span style="color: #0000ff;text-decoration: underline">Two dimensions</span></span></em></p>
<p style="text-align: justify">The second coordinate is usually orthogonal, perpendicular to the first coordinate to avoid a maximum of angle problems and to benefit the simplicity of the calculation for right triangles. Each coordinate has a direction.</p>
<p style="text-align: justify">The position vector is now defined by two components from which we can calculate its length if desired.</p>
<p><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim12.png" rel="lightbox-3"><img class="alignnone size-full wp-image-8647 aligncenter" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim12.png" alt="dim12" width="721" height="567" /></a></p>
<p style="text-align: justify">The addition sign between the two unit vectors is seen as “followed by” and not like the addition of two usual numbers. Another way to write coordinates is to put them in brackets. If we do this, then we don’t write the unit vectors.</p>
<p><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim14.png" rel="lightbox-4"><img class="alignnone size-full wp-image-8648 aligncenter" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim14.png" alt="dim14" width="218" height="30" /></a></p>
<p style="text-align: justify">This system of reference, the Cartesian system, is not the single one that can be used at two dimensions to determine the position of an object. We can also position the object from its distance r to the origin point and an angle θ from one axis. This reference system is called the polar system.</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim15.png" rel="lightbox-5"><img class="alignnone size-full wp-image-8649" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim15.png" alt="dim15" width="411" height="36" /></a></p>
<p style="text-align: justify">It is possible to determine the relation between the coordinates X;Y in the Cartesian system and r;θ in the polar system using the relation defining the cosine, the sinus and the tangent:</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim16.png" rel="lightbox-6"><img class="alignnone size-full wp-image-8664" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim16.png" alt="dim16" width="787" height="218" /></a></p>
<p style="text-align: justify">The unity vector <a href="http://brussels-scientific.com/wp-content/uploads/2018/02/mov3.png" rel="lightbox-7"><img class="alignnone size-full wp-image-8675" src="http://brussels-scientific.com/wp-content/uploads/2018/02/mov3.png" alt="mov3" width="21" height="26" /></a> can thus be calculated.</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim20.png" rel="lightbox-8"><img class="alignnone size-full wp-image-8665" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim20.png" alt="dim20" width="346" height="55" /></a></p>
<p style="text-align: justify">or</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim21.png" rel="lightbox-9"><img class="alignnone size-full wp-image-8666" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim21.png" alt="dim21" width="469" height="61" /></a></p>
<p style="text-align: justify">We can also define the unit vector <a href="http://brussels-scientific.com/wp-content/uploads/2018/02/mov4.png" rel="lightbox-10"><img class="alignnone size-full wp-image-8676" src="http://brussels-scientific.com/wp-content/uploads/2018/02/mov4.png" alt="mov4" width="23" height="27" /></a>:</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim22.png" rel="lightbox-11"><img class="alignnone size-full wp-image-8667" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim22.png" alt="dim22" width="507" height="67" /></a></p>
<p style="text-align: justify">Both polar unity vectors depend thus upon θ that should thus be chosen conscientiously.</p>
<p style="text-align: justify"><em><span style="text-decoration: underline;color: #0000ff">Three dimensions</span></em></p>
<p style="text-align: justify">A third coordinate is added in the reference systems. In the Cartesian system, we add a coordinate that is orthogonal to the two previous ones.</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim17.png" rel="lightbox-12"><img class="alignnone  wp-image-8668" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim17.png" alt="dim17" width="428" height="384" /></a></p>
<p style="text-align: justify">In the polar system, we need a second angle to determine the position of an object. We take the first from the axis x in the xy plane and the second angle is taken from the z axis in the zr plane of the object.</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim23.png" rel="lightbox-13"><img class="alignnone size-full wp-image-8670" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim23.png" alt="dim23" width="405" height="373" /></a></p>
<p style="text-align: justify">Again, the Cartesian system can be associated to the polar system.</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim19.png" rel="lightbox-14"><img class="alignnone size-full wp-image-8671" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim19.png" alt="dim19" width="468" height="152" /></a></p>
<p style="text-align: justify">The unit vectors are defined as</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/02/dim24.png" rel="lightbox-15"><img class="alignnone size-full wp-image-8672" src="http://brussels-scientific.com/wp-content/uploads/2018/02/dim24.png" alt="dim24" width="410" height="99" /></a></p>
<p style="text-align: center">
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=8644">Chapter 3a: the motion- the position</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
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		<title>Chapter 2: quantities and units</title>
		<link>http://brussels-scientific.com/?p=8622</link>
		<comments>http://brussels-scientific.com/?p=8622#comments</comments>
		<pubDate>Wed, 24 Jan 2018 11:07:14 +0000</pubDate>
		<dc:creator><![CDATA[Dr GERARD Thomas]]></dc:creator>
				<category><![CDATA[Physics]]></category>

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		<description><![CDATA[<p>Units are necessary to evaluate quantities. Obviously, a rhinoceros is heavier than a dog, but to know by how much, we need some reference units. Moreover, rhinoceroses don’t all have the same weight. We are thus in need of a consistent unit to measure the weight of objects. The same problem appears for all the [&#8230;]</p>
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=8622">Chapter 2: quantities and units</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
]]></description>
				<content:encoded><![CDATA[<p style="text-align: justify">Units are necessary to evaluate quantities. Obviously, a rhinoceros is heavier than a dog, but to know by how much, we need some reference units. Moreover, rhinoceroses don’t all have the same weight. We are thus in need of a consistent unit to measure the weight of objects. The same problem appears for all the possible measures: we won’t measure with precision a distance with regards to the length of bananas because bananas don’t have a consistent length, and it is not convenient for many countries to use this unit of measure. Men have thus defined some quantities as references, quantities that are constant no matter the time or the external conditions (if not explicitly described). Note that some inaccurate units of measure are still in use in daily activities when accuracy is not that important. For instance, when cooking, we add x spoons of oil without giving explicitly the required weight or volume.</p>
<p style="text-align: justify">On the other hand, we can measure a distance in meters or in miles, the weight in grams or in pounds. All these units have a well-defined value and can serve as reference units. While some countries as the UK or the USA use some different units, international conventions defined an international system of units (SI base units). Their biggest advantage is the simple relation between the units of different quantities. In SI, one millilitre of water occupies one cubic centimetre, weighs one gram, and requires one calorie of energy to heat up by one degree centigrade, which is one percent of the difference between its freezing point and its boiling point. In the American system, you will need to make huge calculations to calculate how much energy it takes to boil a room-temperature gallon of water because you can’t directly relate any of those quantities.</p>
<p style="text-align: justify">The International Bureau of Weights and Measures (French: Bureau international des poids et mesures) is an intergovernmental organization, established to maintain the International System of Units (SI) under the terms of the Metre Convention (Convention du Mètre, May 20<sup>th</sup> 1875). The organisation is usually referred to by its French initialism, BIPM. Its role is to</p>
<ul style="text-align: justify">
<li>establish fundamental standards and scales for the measure of main physical quantities and to conserve the international prototypes;</li>
<li>compare international standards with national standards;</li>
<li>ensure the coordination of the corresponding techniques of measurement;</li>
<li>measure and coordinate the measures of the fundamental, physical constants involved in the above activities.</li>
</ul>
<p style="text-align: justify"><span style="color: #0000ff"><strong>SI Units</strong></span></p>
<p>The definitions of the reference units are mainly made to give them a well-known and fixed value.</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim1b.png" rel="lightbox-0"><img class="alignnone size-full wp-image-8624" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim1b.png" alt="dim1b" width="876" height="372" /></a></p>
<p style="text-align: justify">These definitions fix the speed of light c at 299792458 m/s et the permeability of the void μ<sub>0</sub> at 4π 10<sup>-7</sup> H/m exactly. They also sometimes require some precisions. For instance, we point out that the cesium atom is at rest, that the carbon atoms are not connected, are at rest and in their fundamental state.</p>
<p style="text-align: justify"><span style="color: #0000ff"><strong>Deriving units</strong></span></p>
<p style="text-align: justify">By commodity, some units are the combination of the SI units to express frequently used units.</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim2.png" rel="lightbox-1"><img class="alignnone size-full wp-image-8625" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim2.png" alt="dim2" width="801" height="399" /></a></p>
<p style="text-align: justify">Finally, there are some quantities without specific unit names</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim3.png" rel="lightbox-2"><img class="alignnone size-full wp-image-8626" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim3.png" alt="dim3" width="800" height="302" /></a></p>
<p style="text-align: justify">We can point out a few specific units:</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim4.png" rel="lightbox-3"><img class="alignnone size-full wp-image-8627" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim4.png" alt="dim4" width="798" height="106" /></a></p>
<p style="text-align: justify">To put an end to this section, we will list the prefix of multiples of the SI units.</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim5.png" rel="lightbox-4"><img class="alignnone size-full wp-image-8628" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim5.png" alt="dim5" width="800" height="282" /></a></p>
<p style="text-align: justify"><span style="color: #0000ff"><strong>Dimensional analysis</strong></span></p>
<p style="text-align: justify"><span style="color: #333333">The existence of the IS system means that all the other physical quantities have units that are homogeneous functions of these base units. A function is homogeneous if, making a scale change on all of its variables: <em>x<sub>1</sub> </em><em>→</em> <em>λ</em><em><sub>1</sub></em><em>x<sub>1</sub>, x<sub>2</sub> </em><em>→</em> <em>λ</em><em><sub>2</sub></em><em>x<sub>2</sub>, x<sub>3</sub> </em><em>→</em> <em>λ</em><em><sub>3</sub></em><em>x<sub>3</sub>,</em> … the function itself changes of scale:<em> f(λ</em><em><sub>1</sub></em><em>x<sub>1</sub>,</em><em> λ</em><em><sub>2</sub></em><em>x<sub>2</sub>,</em><em> λ</em><em><sub>3</sub></em><em>x<sub>3</sub>,…) = </em><em>λ</em><em><sub>1</sub></em><em><sup>α1</sup></em><em> λ</em><em><sub>2</sub></em><em><sup>α2</sup></em><em> λ</em><em><sub>3</sub></em><em><sup>α3</sup></em><em>…</em><em>f(</em><em>x<sub>1</sub>,</em> <em>x<sub>2</sub>,</em> <em>x<sub>3</sub>,…).</em> The units of any quantity, let’s call it Q<sub>r</sub> is thus always expressed by a relation like</span></p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim6.png" rel="lightbox-5"><img class="alignnone size-full wp-image-8629" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim6.png" alt="dim6" width="436" height="33" /></a></p>
<p style="text-align: justify">So if we know the units of one physical quantity, and admitting that there is a relation between this quantity and other variables, and knowing the units of those variables, we can guess the relation between the quantities.</p>
<p style="text-align: justify">For instance, we observe the swinging of one object attached to one string: a pendulum. The pendulum oscillates because it falls and it is restrained by the string. We want to determine the relation between the times the pendulum takes to make one oscillation, i.e. the period, to the parameters we guess as important: the mass M of the object, the length L of the string, and the gravity acceleration g that affects each object on the planet. The units of the variables are kg for the mass, m for the length, and m/s² for the acceleration. The period is a time and thus its unit is s. The relation between the variables and the period should be something like this:</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim7.png" rel="lightbox-6"><img class="alignnone size-full wp-image-8630" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim7.png" alt="dim7" width="331" height="34" /></a></p>
<p style="text-align: justify">As there is no kg at the left of the equality, and it is present at the right side of the equation with the exponent a, then we conclude that a=0. Looking at the seconds, their exponent is 1 at the left and -2b at the right, b is thus b=-1/2. Finally, there is no m at the left while it is present at the right side of the equation, thus 0=b+c. As we determined the value of b, we have that c=1/2 and that the global relation is</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim8.png" rel="lightbox-7"><img class="alignnone size-full wp-image-8631" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim8.png" alt="dim8" width="79" height="78" /></a></p>
<p style="text-align: justify">From our dimensional analysis, we determined that the mass of the object has no influence on the period of the oscillation of the pendulum. Note that we did not write the equal sign: the dimensional analysis doesn’t give the true law; it gives clues on the variables but there can still be numerical factors that can be determined experimentally. On the other hand, the dimensional analysis allows to identify wrong laws not respecting the units of the quantities.</p>
<p style="text-align: justify">Let’s analyse a second example: the period T of revolution of planets around the Sun. First we identify the important parameters involved in the problem: the mass M of the Sun, the distance R between the planet and the Sun, and a constant G giving the gravitational force. The units of the parameters are respectively kg, m and kg<sup>-1</sup>m<sup>3</sup>s<sup>-2</sup>. The period is given in seconds s. The law should be of the form T ~ M<sup>a</sup>G<sup>b</sup>R<sup>c</sup>. For the units, we have the relation</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim9.png" rel="lightbox-8"><img class="alignnone size-full wp-image-8632" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim9.png" alt="dim9" width="259" height="29" /></a></p>
<p style="text-align: justify">The next step is to identify the exponent of each unit at the left and the right side of the equation:</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim10.png" rel="lightbox-9"><img class="alignnone size-full wp-image-8633" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim10.png" alt="dim10" width="312" height="74" /></a></p>
<p style="text-align: justify">The law is thus written</p>
<p style="text-align: center"><a href="http://brussels-scientific.com/wp-content/uploads/2018/01/dim11.png" rel="lightbox-10"><img class="alignnone size-full wp-image-8634" src="http://brussels-scientific.com/wp-content/uploads/2018/01/dim11.png" alt="dim11" width="230" height="82" /></a></p>
<p style="text-align: justify">This relation is the expression of the Kepler’s law that describes the trajectory of planets of the solar system.</p>
<p style="text-align: justify"><span style="color: #0000ff"><strong>Scales and orders of magnitude</strong></span></p>
<p style="text-align: justify">An experimental approach is to estimate the order of magnitude of variables that appear in physical processes. Either we measure the characteristics of one well known property of the matter, or we determine a transition zone between two models of description.</p>
<p style="text-align: justify">For instance, we can regroup the matter as solids, liquids and gases. One major difference between these three phases is their density, i.e. the mass of the matter for a given volume, given in kg/m<sup>3</sup>. We can thus regroup liquids as matter with a density with the order of magnitude around 10<sup>3</sup>kg/m<sup>3</sup> (at T=293K, water: 1003kg/m<sup>3</sup>, olive oil: 910kg/m<sup>3</sup>, sulfuric acid: 1834kg/m<sup>3</sup>,…)while gases have a density of order 1 (at T=273K, air: 1.2kg/m<sup>3</sup>, CO<sub>2</sub>: 1.98kg/m<sup>3</sup>, methane: 0.72kg/m<sup>3</sup>,…). Between solids and liquids, there is a factor 10 in density (at T=293K: iron: 7893kg/m<sup>3</sup>, copper: 8954kg/m<sup>3</sup>, gold: 19320kg/m<sup>3</sup>,…). We will want to determine the temperature at which a solid becomes liquid, i.e. its melting temperature.</p>
<p style="text-align: justify">As the interactions between particles of a solid differ from the interactions between particles in a gas, laws are not the same at the microscopic scale than in the astronomic scale, not because the interactions mysteriously disappear, but because we can neglect some interactions. For instance, imagine an interaction between particles that depends directly on the distance between two particles and one interaction that depends on the third power of the distance. If the distance is small, both interactions will have an effect, but as soon as the distance gets large, we can neglect the first interaction.</p>
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=8622">Chapter 2: quantities and units</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
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		<title>Chapter 1: Elementary physics &#8211; Introduction</title>
		<link>http://brussels-scientific.com/?p=8618</link>
		<comments>http://brussels-scientific.com/?p=8618#comments</comments>
		<pubDate>Fri, 19 Jan 2018 12:00:51 +0000</pubDate>
		<dc:creator><![CDATA[Dr GERARD Thomas]]></dc:creator>
				<category><![CDATA[1st Year]]></category>
		<category><![CDATA[College - Main subjects]]></category>
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		<description><![CDATA[<p>Definitions and laws “One of the noblest desire of the man is to know the laws ruling the Universe, and those who contributed to enlighten some of the mysteries were always admired by their peers; they appear as privileged, wearing on them the divine light, a through centuries the generations gaze upon their indelible work [&#8230;]</p>
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=8618">Chapter 1: Elementary physics &#8211; Introduction</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
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				<content:encoded><![CDATA[<p><span style="color: #0000ff;"><strong>Definitions and laws</strong></span></p>
<p style="text-align: justify;"><em>“One of the noblest desire of the man is to know the laws ruling the Universe, and those who contributed to enlighten some of the mysteries were always admired by their peers; they appear as privileged, wearing on them the divine light, a through centuries the generations gaze upon their indelible work and rank them first amongst the glories of the humanity.”</em></p>
<p style="text-align: justify;">From Achille Cazin (Hachette, 1881).</p>
<p style="text-align: justify;">Physics can be defined as a <em>science that studies the general properties of matter, space, and time, and establishes laws that describe natural phenomena.</em> We will point out the word <strong>law</strong> first, and ask ourselves if we can clearly, and without ambiguity, define all the objects we are discussing, i.e. space, time and matter. Their definitions are (Oxford dictionaries)</p>
<ul style="text-align: justify;">
<li>Space: A continuous area or expanse which is free, available, or unoccupied.</li>
<li>Matter: Physical substance in general, as distinct from mind and spirit; (in physics) that which occupies space and possesses rest mass, especially as distinct from energy.</li>
<li>Time: The indefinite continued progress of existence and events in the past, present, and future regarded as a whole.</li>
</ul>
<p style="text-align: justify;">It is not what we can call clearly defined terms and it doesn’t indicate any of the relations that may exist between them. If we go back in time, Isaac Newton gave its definitions (1687):</p>
<ul style="text-align: justify;">
<li>The absolute space, which is without any relation with anything from the surroundings, is always unchanging and immobile. The relative space is any measure or mobile dimension of this space, which is defined with regards to its position with regards to objects that we consider as the immobile space…</li>
<li>The quantity of matter is the measure that we obtain from its density and its volume…</li>
<li>The absolute time, true and mathematic, is without relation to anything from the surroundings, and by its nature flows uniformly. The relative time, is any measure, accurate or not, of the duration of an event, that we use in place of the true time. I.e. the hour, day, month,…</li>
</ul>
<p style="text-align: justify;">It is difficult to avoid cross references and circular definitions. We will abandon the idea to define everything and accept the fact that some notions can make sense without being explicit. Physics is seeking for the laws that rule the reciprocal actions between one object and its surrounding. Enouncing those laws is not an easy job, and we have seen many changes in the history, as the understanding of the scientists evolved. For instance, L. Wouters gives in a school book of 1916 the law for the dilatation of bodies due to heat as</p>
<p style="text-align: justify;"><em>“The first effect that heat produces on bodies is to increase their volume, to dilate them”</em></p>
<p style="text-align: justify;">This law is based upon its hypothesis on the nature of heat:</p>
<p style="text-align: justify;"><em>“Based on the modern hypothesis on the nature of heat, it results from the vibratory movement of the smallest molecules of the ponderable matter, and is transmitted via a fluid called aether. Aether is a subtle, perfectly elastic, substance that fills the intermolecular spaces as well as the so-called interplanetary voids. Heat is, at the end, a particular state of movement.”</em></p>
<p style="text-align: justify;">Today, it is obvious that this law is false, mostly because of the notion of aether it is based on. The law itself is true with some exceptions. So, shall we give no definition nor law? Obviously we will, but laws should results from the simple relations obtained from experimentations: if I modify one physical quantity of my experiment, then another physical quantity changes, at this effect is repeated consistently if I repeat the experiment.</p>
<p style="text-align: justify;">To end this introduction, I will extend the citation of Achille Cazin (Hachette, 1881) I opened the introduction with.</p>
<p style="text-align: justify;"><em>“No matter the study on which we work, there are some general rules that one must follow to avoid falling in annoying confusions. …</em></p>
<p style="text-align: justify;"><em>In physics, we observe all the circumstances around a natural phenomenon; we measure all the available quantities; we seek relations between theses quantities, and these relations are called the law of the phenomenon. When the phenomenon is too complex, and it looks like it is impossible to state one unique law, we modify the phenomenon, we make an experiment. Some circumstances seeming ancillary, are made negligible, and we observe the dominating quantities. From this experiment we obtain an approximate law, and by extension we seek the influence of the neglected circumstances, in which way they alter the law. Doing that, we find the limit law towards which tends the observed law when the circumstances become more and more negligible. Such a law is then used as a fundamental principle, seen as the temporary expression of a physical truth, temporary because one more accurate observation or a new phenomenon can modify the conclusions admitted as truth until now.”</em></p>
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=8618">Chapter 1: Elementary physics &#8211; Introduction</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
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		<title>Chapter2: torque and angular momentum in circular motion</title>
		<link>http://brussels-scientific.com/?p=2983</link>
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		<pubDate>Sat, 07 Feb 2015 00:12:19 +0000</pubDate>
		<dc:creator><![CDATA[Dr ABDOLMOHAMMADI AKBAR]]></dc:creator>
				<category><![CDATA[1st Year]]></category>
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		<description><![CDATA[<p>Definitions: the torque and angular momentum are defined as vector products of position, force and momentum. Suppose a forceacts on a particle whose position with respect to the origin 0 is the displacement vector . Then the torque “about the point 0 and acting on the particle,” is defined as: Now suppose the particle has [&#8230;]</p>
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=2983">Chapter2: torque and angular momentum in circular motion</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
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				<content:encoded><![CDATA[<p style="text-align: justify;"><strong><span style="color: #0000ff;">Definitions</span>:</strong> the torque and angular momentum are defined as vector products of position, force and momentum. Suppose a force<a href="http://brussels-scientific.com/wp-content/uploads/2015/02/BIMAR-1.png" rel="lightbox-0"><img class="alignnone size-full wp-image-2993" src="http://brussels-scientific.com/wp-content/uploads/2015/02/BIMAR-1.png" alt="BIMAR 1" width="20" height="20" /></a>acts on a particle whose position with respect to the origin 0 is the displacement vector <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/BIMAR-3.png" rel="lightbox-1"><img class="alignnone size-full wp-image-2995" src="http://brussels-scientific.com/wp-content/uploads/2015/02/BIMAR-3.png" alt="BIMAR 3" width="18" height="24" /></a>. Then the torque “about the point 0 and acting on the particle,” is defined as:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/FINAL-TORQUE.png" rel="lightbox-2"><img class="alignnone  wp-image-2991" src="http://brussels-scientific.com/wp-content/uploads/2015/02/FINAL-TORQUE-300x154.png" alt="FINAL TORQUE" width="329" height="169" /></a><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/BIMAR-4.png" rel="lightbox-3"><img class="alignnone  wp-image-2996" src="http://brussels-scientific.com/wp-content/uploads/2015/02/BIMAR-4.png" alt="BIMAR 4" width="135" height="60" /></a></p>
<p style="text-align: justify;">Now suppose the particle has a liner momentum P relative to the origin. Then the angular momentum of the particle is defined as:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/Angular-Momentum.png" rel="lightbox-4"><img class="alignnone size-medium wp-image-2998" src="http://brussels-scientific.com/wp-content/uploads/2015/02/Angular-Momentum-300x187.png" alt="Angular Momentum" width="300" height="187" /></a><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/FETE-TETE-2.png" rel="lightbox-5"><img class="alignnone  wp-image-3001" src="http://brussels-scientific.com/wp-content/uploads/2015/02/FETE-TETE-2.png" alt="FETE TETE 2" width="168" height="77" /></a></p>
<p style="text-align: justify;">The direction of <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/MAMOUR-1.png" rel="lightbox-6"><img class="alignnone size-full wp-image-3003" src="http://brussels-scientific.com/wp-content/uploads/2015/02/MAMOUR-1.png" alt="MAMOUR 1" width="23" height="23" /></a> and <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/MAMOUR-2.png" rel="lightbox-7"><img class="alignnone size-full wp-image-3004" src="http://brussels-scientific.com/wp-content/uploads/2015/02/MAMOUR-2.png" alt="MAMOUR 2" width="28" height="26" /></a> are given by the right-hand rule for cross products.</p>
<p style="text-align: justify;"><span style="color: #0000ff;"><strong>Relationship: </strong></span> =  Using the definitions of torque and angular momentum, we can derive a useful relationship between them.</p>
<p style="text-align: justify;"><span style="color: #800080;">Starting from Newton’s second law, written in the form:</span></p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-1.png" rel="lightbox-8"><img class="alignnone  wp-image-3010" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-1.png" alt="DIVANE 1" width="145" height="71" /></a></p>
<p style="text-align: justify;"><strong><span style="color: #0000ff;">The torque is:</span></strong></p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-2.png" rel="lightbox-9"><img class="alignnone  wp-image-3011" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-2.png" alt="DIVANE 2" width="226" height="59" /></a></p>
<p style="text-align: justify;">This can be rewritten using the expression for the derivative of a cross product:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-3.png" rel="lightbox-10"><img class="alignnone  wp-image-3013" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-3.png" alt="DIVANE 3" width="244" height="53" /></a><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-4.png" rel="lightbox-11"><img class="alignnone  wp-image-3014" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-4.png" alt="DIVANE 4" width="148" height="68" /></a></p>
<p style="text-align: justify;">Now<a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-5.png" rel="lightbox-12"><img class="alignnone size-full wp-image-3015" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-5.png" alt="DIVANE 5" width="71" height="31" /></a>  so  <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-6.png" rel="lightbox-13"><img class="alignnone size-full wp-image-3019" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-6.png" alt="DIVANE 6" width="64" height="24" /></a> (because the vector product of parallel vectors is zero), so the torque is:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-7.png" rel="lightbox-14"><img class="alignnone  wp-image-3021" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-7.png" alt="DIVANE 7" width="172" height="84" /></a></p>
<p style="text-align: justify;">Thus the time rate of change of the angular momentum of a particle is equal to the torque acting on it.<strong> </strong></p>
<p style="text-align: justify;"><span style="color: #0000ff;"><strong>Motion confined to a plane: </strong></span></p>
<p style="text-align: justify;">The expression <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/divane-8.png" rel="lightbox-15"><img class="alignnone  wp-image-3024" src="http://brussels-scientific.com/wp-content/uploads/2015/02/divane-8.png" alt="divane 8" width="108" height="30" /></a>  for a particle takes on a scalar appearance when the motion of the particle is confined to a plane.</p>
<p style="text-align: justify;">Consider a particle constrained to move only in the <em>x-y</em> plane, as shown in Fig.2. the torque on the particle is always perpendicular to this plane as is the angular momentum .</p>
<p style="text-align: justify;">Equivalently, we say that<a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-9.png" rel="lightbox-16"><img class="alignnone size-full wp-image-3026" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-9.png" alt="DIVANE 9" width="27" height="25" /></a>  and<a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-10.png" rel="lightbox-17"><img class="alignnone size-full wp-image-3027" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-10.png" alt="DIVANE 10" width="25" height="24" /></a>  have only <em>z</em>-components. Since their directions remain constant, only their magnitudes change. Then:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-12.png" rel="lightbox-18"><img class="alignnone  wp-image-3029" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-12.png" alt="DIVANE 12" width="222" height="38" /></a></p>
<p style="text-align: justify;">This equation holds only if <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-13.png" rel="lightbox-19"><img class="alignnone size-full wp-image-3030" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-13.png" alt="DIVANE 13" width="70" height="26" /></a>are in the same plane; if not (and they won’t be for non-planar motion), the full Eq. must be used.</p>
<p style="text-align: justify;"><strong><span style="color: #0000ff;">Circular motion of a Mass:</span></strong> The torque and angular momentum for the special case of a single particle in circular motion can be easily related to the particle’s angular variables. Supposed a particle of mass m moves about a circle of radius r with speed v (not necessarily constant) as shown in Fig.3. The particle’s angular momentum is:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-11.png" rel="lightbox-20"><img class="alignnone  wp-image-3031" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-11.png" alt="DIVANE 11" width="168" height="55" /></a></p>
<p style="text-align: justify;">But since <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-14.png" rel="lightbox-21"><img class="alignnone size-full wp-image-3033" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-14.png" alt="DIVANE 14" width="69" height="24" /></a> are perpendicular, the magnitude of L is:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-15.png" rel="lightbox-22"><img class="alignnone  wp-image-3034" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-15.png" alt="DIVANE 15" width="158" height="44" /></a></p>
<p style="text-align: justify;">And the direction is out of the page. This equation  may be rewritten in terms of the angular velocity (since <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-16.png" rel="lightbox-23"><img class="alignnone size-full wp-image-3035" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-16.png" alt="DIVANE 16" width="59" height="14" /></a>) as:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-17.png" rel="lightbox-24"><img class="alignnone  wp-image-3036" src="http://brussels-scientific.com/wp-content/uploads/2015/02/DIVANE-17.png" alt="DIVANE 17" width="158" height="43" /></a></p>
<p style="text-align: justify;"><strong><span style="color: #0000ff;">Similarly, the torque is:</span></strong></p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/SHADI-1.png" rel="lightbox-25"><img class="alignnone  wp-image-3039" src="http://brussels-scientific.com/wp-content/uploads/2015/02/SHADI-1.png" alt="SHADI 1" width="213" height="40" /></a></p>
<p style="text-align: justify;">Where α is the particle’s angular acceleration.</p>
<p style="text-align: justify;"><span style="text-decoration: underline; color: #800080;"><strong>Systems of Particles</strong></span></p>
<p style="text-align: justify;"><strong><span style="color: #0000ff;">Total Angular Momentum:</span>  </strong>The total angular momentum of a system of particles is simply the sum of the angular momenta of the individual particles, added vectorially. Let <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/SHADI-3.png" rel="lightbox-26"><img class="alignnone size-full wp-image-3040" src="http://brussels-scientific.com/wp-content/uploads/2015/02/SHADI-3.png" alt="SHADI 3" width="106" height="25" /></a> be the respective angular momenta, about a given point, of the particles in the system. The total angular momentum about the point is:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/SHADI-2.png" rel="lightbox-27"><img class="alignnone  wp-image-3041" src="http://brussels-scientific.com/wp-content/uploads/2015/02/SHADI-2.png" alt="SHADI 2" width="217" height="44" /></a></p>
<p style="text-align: justify;">As time passes, the total angular momentum may change. Its rate of change <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/shadi-4.png" rel="lightbox-28"><img class="alignnone size-full wp-image-3043" src="http://brussels-scientific.com/wp-content/uploads/2015/02/shadi-4.png" alt="shadi 4" width="46" height="24" /></a>, will be the sum of the rates <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/shadi-5.png" rel="lightbox-29"><img class="alignnone size-full wp-image-3044" src="http://brussels-scientific.com/wp-content/uploads/2015/02/shadi-5.png" alt="shadi 5" width="54" height="21" /></a> for the particles in the system. Thus <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/shadi-6.png" rel="lightbox-30"><img class="alignnone size-full wp-image-3045" src="http://brussels-scientific.com/wp-content/uploads/2015/02/shadi-6.png" alt="shadi 6" width="48" height="22" /></a> will equal the sum of the torques acting on the particles.</p>
<p style="text-align: justify;"><span style="color: #0000ff;"><strong>Total Torque:</strong></span> The total torque on a system of particles is just the sum of the external torques acting on the system. The torque due to internal forces is zero because by Newton’s third law the forces between any two particles are equal and opposite and directed along the line connecting them. The net torque due to each such action-reaction force pair is zero so the total internal torque must also be zero. Then the total torque on the system is just equal to the sum of the external torques:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-1.png" rel="lightbox-31"><img class="alignnone  wp-image-3048" src="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-1.png" alt="torque 1" width="319" height="33" /></a></p>
<p style="text-align: justify;">For the system, then:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-2.png" rel="lightbox-32"><img class="alignnone size-full wp-image-3049" src="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-2.png" alt="torque 2" width="63" height="32" /></a></p>
<p style="text-align: justify;">In words, the time rate of change of the total angular momentum about a given point, for a system of particles, is equal to the sum of the external torques about that point and acting on the system.</p>
<p style="text-align: justify;"><span style="color: #0000ff;"><strong>Rigid Body Motion About a Fixed Axis:</strong></span> A rigid body is a system of particles whose positions are all fixed relative to each other. Since <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-3.png" rel="lightbox-33"><img class="alignnone size-full wp-image-3051" src="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-3.png" alt="torque 3" width="122" height="19" /></a> <strong> </strong>for each particle in the body, we may write for the total angular momentum:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-4.png" rel="lightbox-34"><img class="alignnone  wp-image-3052" src="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-4.png" alt="torque 4" width="200" height="42" /></a></p>
<p style="text-align: justify;">Where we have assumed that the body is rotating about a fixed axis with angular velocity :   <a href="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-5.png" rel="lightbox-35"><img class="alignnone wp-image-3053 " src="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-5.png" alt="torque 5" width="85" height="31" /></a></p>
<p style="text-align: justify;">And, since the axis of rotation is fixed, equations with a scalar appearance         hold for the torque:</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-akhar.png" rel="lightbox-36"><img class="alignnone  wp-image-3055" src="http://brussels-scientific.com/wp-content/uploads/2015/02/torque-akhar.png" alt="torque akhar" width="200" height="43" /></a></p>
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=2983">Chapter2: torque and angular momentum in circular motion</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
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		<title>Chapter 1: uniform circular motion</title>
		<link>http://brussels-scientific.com/?p=2947</link>
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		<pubDate>Thu, 29 Jan 2015 00:50:03 +0000</pubDate>
		<dc:creator><![CDATA[Dr ABDOLMOHAMMADI AKBAR]]></dc:creator>
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		<description><![CDATA[<p>When an object has a circular motion even though its speed is constant, it is nonetheless accelerating because according to newton’s 1st law: an object continues in its state of rest or uniform motion unless acted on by an external force. So if the object was to be free in space then of course it will [&#8230;]</p>
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=2947">Chapter 1: uniform circular motion</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
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				<content:encoded><![CDATA[<p style="text-align: justify;">When an object has a circular motion even though its speed is constant, it is nonetheless accelerating because according to newton’s 1st law: an object continues in its state of rest or uniform motion unless acted on by an external force. So if the object was to be free in space then of course it will continue to travel tangentially in the direction that it has just before.</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/01/UCM.jpg" rel="lightbox-0"><img class="alignnone  wp-image-2948" src="http://brussels-scientific.com/wp-content/uploads/2015/01/UCM-300x187.jpg" alt="UCM" width="518" height="323" /></a></p>
<p style="text-align: justify;">But if it changes the direction of the velocity ( the change of the velocity is acceleration). In fact,this acceleration is always towards the center of the circle and it’s called centripetal acceleration. And if we have an acceleration then the newton’s second law must be applicable which says: the force is equal to  mass times acceleration (F= m.a )  then the centripetal force = mass  X centripetal acceleration.</p>
<p style="text-align: justify;">If the speed of objet is<a href="http://brussels-scientific.com/wp-content/uploads/2015/01/X1.png" rel="lightbox-1"><img class="alignnone size-full wp-image-2951" src="http://brussels-scientific.com/wp-content/uploads/2015/01/X1.png" alt="X1" width="17" height="22" /></a> and the radius of circle is R, then if the objet travels around one time, the distance that it travels is =2πR, it’s simply the circumference of the circle and imagine it does that in 60 seconds,so the velocity will be <a href="http://brussels-scientific.com/wp-content/uploads/2015/01/X3.png" rel="lightbox-2"><img class="alignnone wp-image-2953" src="http://brussels-scientific.com/wp-content/uploads/2015/01/X3.png" alt="X3" width="41" height="38" /></a>  in m/sec.</p>
<p style="text-align: justify;">The another way of measuring is the angular speed and we know that the whole circle is 360°=2π. We use radians to measure angular speed, radians =<a href="http://brussels-scientific.com/wp-content/uploads/2015/01/X4.png" rel="lightbox-3"><img class="alignnone  wp-image-2954" src="http://brussels-scientific.com/wp-content/uploads/2015/01/X4.png" alt="X4" width="81" height="72" /></a></p>
<p style="text-align: justify;">How many radians are there in a full circle? Full circle will be 2πR.</p>
<p style="text-align: justify;"><span style="color: #0000ff;">Angular speed:</span> is designed by ω and ω=2π/t  radians/second and we know that V= 2πR/t  that means <span style="color: #800080;">V= ωR</span>, So this formula shows the relationship between the V (orbital velocity) and ω (angular velocity) .</p>
<p style="text-align: justify;"><span style="color: #0000ff;">Frequency (ƒ):</span> is the number of cycles per second, we know that ω is the number of radians per second and we know that 2π is the number of radians per cycle then<span style="color: #800080;"> ƒ= ω/2π </span>and we can write <span style="color: #800080;">ω= 2πƒ</span>.</p>
<p style="text-align: justify;"><span style="color: #0000ff;">Period (T)</span>, is the amount of time it takes to do one cycle And <span style="color: #800080;">T= 1/ƒ</span> so if <span style="color: #800080;">ω=2πƒ </span> then<span style="color: #800080;"> ω=2π/T</span></p>
<p style="text-align: justify;"><span style="text-decoration: underline;"><span style="color: #0000ff; text-decoration: underline;">Centripetal acceleration:</span></span></p>
<p style="text-align: justify;">Imagine the objet with a speed<a href="http://brussels-scientific.com/wp-content/uploads/2015/01/X1.png" rel="lightbox-1"><img class="alignnone size-full wp-image-2951" src="http://brussels-scientific.com/wp-content/uploads/2015/01/X1.png" alt="X1" width="17" height="22" /></a> at point a  and after a short distance it will be at point b which will have an angle dθ (a very small angle).The distance travelled will be called dx (a small distance).</p>
<p style="text-align: justify;"><a href="http://brussels-scientific.com/wp-content/uploads/2015/01/UCM.jpg" rel="lightbox-0"><img class="alignnone size-medium wp-image-2948" src="http://brussels-scientific.com/wp-content/uploads/2015/01/UCM-300x187.jpg" alt="UCM" width="300" height="187" /></a></p>
<p style="text-align: justify;">The time of travelling = dt, so the objet travels a small distance (dx) sweeping out an angle called (dθ) and it does that in a short time (dt).</p>
<p style="text-align: justify;">When it will be at b, the speed is still<a href="http://brussels-scientific.com/wp-content/uploads/2015/01/X1.png" rel="lightbox-1"><img class="alignnone size-full wp-image-2951" src="http://brussels-scientific.com/wp-content/uploads/2015/01/X1.png" alt="X1" width="17" height="22" /></a>  because it doesn’t change the speed but it will be now in a different direction and if the speed changes that means the objet has been subjected to an acceleration.</p>
<p style="text-align: justify;">                                               <a href="http://brussels-scientific.com/wp-content/uploads/2015/01/X5.png" rel="lightbox-7"><img class="alignnone size-full wp-image-2965" src="http://brussels-scientific.com/wp-content/uploads/2015/01/X5.png" alt="X5" width="69" height="40" /></a>          <a href="http://brussels-scientific.com/wp-content/uploads/2015/01/X6.png" rel="lightbox-8"><img class="alignnone  wp-image-2966" src="http://brussels-scientific.com/wp-content/uploads/2015/01/X6.png" alt="X6" width="57" height="45" /></a>     <span style="color: #800080;">dx= Rdθ    and dx= Vdt</span></p>
<p style="text-align: justify;">Acceleration is the change of velocity during the time. To calculate the difference between two vectors we must put them tail to tail.what we are looking for is the streight line dy  we know <span style="color: #800080;">dθ= dy/v</span> (small circle with r=v )</p>
<p style="text-align: justify;">If dθ is very small, then the arc length y becomes the straight line <span style="color: #800080;">dθ=dv/v</span></p>
<p style="text-align: justify;"><em>dx =Rdθ (=Rdv/v)      dx= Vdt       ⇒Rdv/v= vdt    ⇒Rdv/dt= <a href="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI-4.png" rel="lightbox-9"><img class="alignnone size-full wp-image-2969" src="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI-4.png" alt="AZADI 4" width="39" height="27" /></a>⇒ dv/dt =<a href="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI5.png" rel="lightbox-10"><img class="alignnone  wp-image-2970" src="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI5.png" alt="AZADI5" width="24" height="34" /></a>= a</em></p>
<p style="text-align: justify;">we know v = ωR  ⇒           a =<a href="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI5.png" rel="lightbox-10"><img class="alignnone  wp-image-2970" src="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI5.png" alt="AZADI5" width="31" height="44" /></a>=<a href="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI-8.png" rel="lightbox-12"><img class="alignnone  wp-image-2974" src="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI-8.png" alt="AZADI 8" width="98" height="46" /></a> and  F= m.a</p>
<p> F= centripetal force = <a href="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI-9.png" rel="lightbox-13"><img class="alignnone size-full wp-image-2976" src="http://brussels-scientific.com/wp-content/uploads/2015/01/AZADI-9.png" alt="AZADI 9" width="111" height="50" /></a></p>
<p>The post <a rel="nofollow" href="http://brussels-scientific.com/?p=2947">Chapter 1: uniform circular motion</a> appeared first on <a rel="nofollow" href="http://brussels-scientific.com/?page_id=550">BORZUYA UNIVERSITY</a>.</p>
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